(sin(2pi-x)tg(3pi/2--x)-cos(x-pi)-sin(x-pi))^2 + cos^2(pi-x) =
= (-sinxctgx -(-cosx)-(-sinx))^2+cos^2x = (-sinxcosx/sinx+cosx+sinx)^2 + cos^2x =
= (-cosx+cosx+sinx)^2 + cos^2x = sin^2x + cos^2x = 1
ответ. 1
(sin(2pi-x)tg(3pi/2--x)-cos(x-pi)-sin(x-pi))^2 + cos^2(pi-x) =
= (-sinxctgx -(-cosx)-(-sinx))^2+cos^2x = (-sinxcosx/sinx+cosx+sinx)^2 + cos^2x =
= (-cosx+cosx+sinx)^2 + cos^2x = sin^2x + cos^2x = 1
ответ. 1