1.2. Определить вес воды в рукавах диаметром 66 мм и 77 мм и длиной 20 м.
ответ: G1 = 670 9, H;G2 = 913 2, H .
гогогогог
1
11.07.2021 17:25
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Если уже есть ответы, то я напишу формулу:
P=pgπd²/4
p - плотность воды
g - ускорение свободного падения
d - диаметр