7. Solve these problems: 1. Suppose that you have four electric cells. The current capacity of each cell equals 1.5 amp, the voltage output equals 2 V. a) Connect the cells in series. In what way should it be done? b) Connect the battery to a circuit whose resistance value equals I 5 ohms. What is the value of current in the circuit? 2. Suppose that you have three cells of the same value. a) Connect them in parallel. In what way should it be done? b) Connect the second battery to the same circuit: what will it result in? Suppose that one of the cells stops operating. What should be done in this case?

1. Let's start by looking at the first problem.

a) Connecting the cells in series means connecting one end of the first cell to the positive end of the second cell, and so on until the last cell. The negative end of the first cell will be connected to the positive end of the second cell, and so on until the negative end of the last cell. By doing this, we create a series circuit where the voltage adds up but the current capacity remains the same. So, in this case, we would connect the positive end of the first cell to the negative end of the second cell, and continue this pattern until we have all four cells connected.

b) Now, let's move on to the second part of the question. We have the battery connected to a circuit with a resistance of 5 ohms. To find the current in the circuit, we can use Ohm's Law, which states that I = V/R, where I is the current, V is the voltage, and R is the resistance. In this case, the voltage output of each cell is 2 V, so the total voltage in the circuit would be 2 V x 4 = 8 V. Therefore, the current in the circuit would be I = 8 V / 5 ohms = 1.6 amp.

2. Now let's move on to the second problem.

a) Connecting the cells in parallel means connecting the positive ends of all three cells together and the negative ends together. By doing this, we create a parallel circuit where the voltage remains the same but the current capacity adds up. So, in this case, we would connect the positive ends of all three cells together and the negative ends together.

b) Now, let's assume that the second battery is connected to the same circuit. This means that the positive end of the second battery will be connected to the positive end of the first battery, and the negative end of the second battery will be connected to the negative end of the first battery. By doing this, we increase the total voltage in the circuit, as the voltage of each individual cell adds up. So, if each cell has a voltage output of 2 V, then adding the second battery would result in a total voltage of 2 V + 2 V = 4 V.

c) Lastly, if one of the cells in the parallel circuit stops operating, it will not affect the functioning of the other cells. The remaining cells will continue to provide current to the circuit. However, if we want to remove the faulty cell, we can simply disconnect it from the circuit. The other cells will still provide current, and the circuit will continue to work.