(x2+5x+1)(x2+5x+3)+1=0
(x2+5x+2) = t
(t - 1)(t + 1) + 1 = 0
t2 - 1 + 1 = 0
t = 0
x2+5x+2 = 0
D = 25 - 8 = 17
x12 = (-5 +- √17)/2
(x2+5x+1)(x2+5x+3)+1=0
(x2+5x+2) = t
(t - 1)(t + 1) + 1 = 0
t2 - 1 + 1 = 0
t = 0
x2+5x+2 = 0
D = 25 - 8 = 17
x12 = (-5 +- √17)/2