Выражение (a-2)(a-11)-2a(4-3a) (a-8)(2a-1)(3a+1)(5a-2) заранее

1) (a-2)(a-11)-2a(4-3a)=a²-11a-2a+22-8a+6a²=7a²-21a+22.
2) (a-8)(2a-1)(3a+1)(5a-2)=(2a²-a-16a+8)(3a+1)(5a-2)=(2a²-17a+8)(3a+1)(5a-2)=(6a³+2a²-51a²-17a+24+8)(5a-2)=(6a³-49a²+7a+8)(5a-2)=30a⁴-12a³-245a³+98a²+35a²-14a²+40a-16=3a⁴-257a³+133a²+26a-16.