naidem ugol A=90-Btogda sinA=sin(90-B)=cosB=√1-4/13=3/√13
dalshe po teoreme sinusov:
AC/sinB=BC/sinA
BC=AC*cosB/sinB=6*3*√13/2√13=9
решение во вложении
naidem ugol A=90-B
togda sinA=sin(90-B)=cosB=√1-4/13=3/√13
dalshe po teoreme sinusov:
AC/sinB=BC/sinA
BC=AC*cosB/sinB=6*3*√13/2√13=9
решение во вложении