1. 2cos(-x) - √2 = 0
2cosx = √2
cosx = 0,5√2
х = ±π/4 + 2πn n∈Z
2. sin(x/3+П/4)=-1
x/3+π/4 = -π/2 +2πn
x/3 = -π/2 +2πn - π/4
x/3 = -3π/4 +2πn
x = -9π/4 +6πn n∈Z
1) 2cos(-x)=√2;
cosx=√2/2;
x=±π/4+2πn. n∈Z.
2) sin(x/3+π/4)=-1;
x/3+π/4=y;
siny=-1;
y=-π/2+2πn. n∈Z.
x/3=-π/2-π/4+2πn. n∈Z.
x/3=-3π/4+2πn. n∈Z.
x=-9π/4+6πn. n∈Z.
Вроде так...
1. 2cos(-x) - √2 = 0
2cosx = √2
cosx = 0,5√2
х = ±π/4 + 2πn n∈Z
2. sin(x/3+П/4)=-1
x/3+π/4 = -π/2 +2πn
x/3 = -π/2 +2πn - π/4
x/3 = -3π/4 +2πn
x = -9π/4 +6πn n∈Z
1) 2cos(-x)=√2;
cosx=√2/2;
x=±π/4+2πn. n∈Z.
2) sin(x/3+π/4)=-1;
x/3+π/4=y;
siny=-1;
y=-π/2+2πn. n∈Z.
x/3=-π/2-π/4+2πn. n∈Z.
x/3=-3π/4+2πn. n∈Z.
x=-9π/4+6πn. n∈Z.
Вроде так...