- Алгебра
- Там должен выйти (2,1;3,5]
Там должен выйти (2,1;3,5]
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Объяснение:
ответ: x∈[2;6,5).
4(х+1)<3(х-3)-х
4(2х-1)=<3(3х-2)
4х+4<3х-9-х
8х-4=<9х-6
4х-3х+х<-9-4
8х-9х=<-6+4
2х<-13
-х=<-2
х<7,5
х=<2
(2; 7,5]
не знаю почему у вас ответ другой