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((-2log5 15)^2-(log5 9)^2+3*log5 15* log5 9)/log5 9-log5 15

MaryOnegina MaryOnegina    2   03.10.2019 18:04    0

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Yaritas Yaritas  09.10.2020 15:02

(-2log²5 15 - log²5 9 + 3*log5 15* log5 9)/(log5 9-log5 15) =

(-(log²5 15  - 2*log5 15* log5 9 + log²5 9) + log5 15* log5 9 - log²5 15 )/(log5 9-log5 15) =

(-(log5 9  - log5 15)² + log5 15 (log5 9 - log5 15) )/(log5 9-log5 15) =

(log5 9  - log5 15)( log5 15 - (log5 9 - log5 15) )/(log5 9-log5 15) =

log5 15 - log5 9 + log5 15 = log5 (15*15)/9 = log5 (5²3²)/9 = log5 5² = 2  

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