Решите уравнение .(x-2)(x+3)=x(2-x)

(x-2)(x+3)=x(2-x)
x^2 + 3x - 2x - 6 = 2x - x^2
x^2 + 3x - 2x - 6 - 2x + x^2 = 0
2x^2 - x - 6 = 0
Ищем дискриминант.
D = b + 4ac = (-1)^2 + 4*2*6 = 1 + 48 = 49
x1 = -b + √D/2a = 1+ 7/2*2 = 8/ = 4
x2 = -b - √D/2a = 1 - 7/2*2 = -6/4 = -1,5