Решите уравнение; (4+x)^7=-128; (10x)^2=900; 3^3k=729; 7^5n^-2=343

(4+x)^7 = -128
(4+x)^7 = (-2)^7
4 + х = -2
х = -2/4
х = -1/2
х = -0,5


(10x)^2=900
10х = ± √900
10х = ± 30
▪х1 = 30÷10
х1 = 3
▪х2 = -30÷10
х2 = -3


3^(3k) = 729
3^(3k) = 3^6
3k = 6
k = 6÷3
k = 2


(7^5)(n^-2)=343. ОДЗ: n≠0
7^5/n^2 = 343
343n^2 = 7^5
(7^3)(n^2) = 7^5
n^2 = 7^5/7^3
n^2 = 7^2
n = ± 7