ответ:\frac{3x-x^{2}}{2} +\frac{2x^{2}-x }{6} =x
3(3x-x²)+2x²-x=6x
9x - 3x²+2x² - 6x=0
3x - x²=0
x(3-x)=0
x1=0
3-x=0
x2=3
ответ:\frac{3x-x^{2}}{2} +\frac{2x^{2}-x }{6} =x
3(3x-x²)+2x²-x=6x
9x - 3x²+2x² - 6x=0
3x - x²=0
x(3-x)=0
x1=0
3-x=0
x2=3