Решите уравнение 3/(х-2)2(в квадрате) + 5/х-2 - 8=0

( 3 + 5(x - 2)) / (x - 2)^2 = 8
( 3 + 5x - 10) / (x - 2)^2 =8
( 5x - 7)/(x - 2)^2 =8
8(x - 2)^2 = 5x - 7
8( x^2 - 4x + 4) = 5x - 7
8x^2 - 32x + 32 - 5x + 7 = 0
8x^2 - 37x + 39 = 0
D = b^2 - 4ac = 1369 - 1248 = 121 = 11^2
x1 = ( 37 + 11) / 16 = 3
x2 = ( 37 - 11) / 16 = 1,625