Решите систему и желательно с подробным )) первое: x+2=4-y второе: x^2+(y-3)^2-5^2=0

X+2=4-y
x^2+(y-3)^2-5^2=0

x=2-y
(2-y)^2+(y-3)^2-5^2=0
(2-y)(2-y)+(y-3)(y-3)-5^2=0
(4-2y-2y+y^2)+(y^2-6y+9)-5^2=0
(y^2-4y+4)+(y^2-6y+9)-5^2=0
2y^2-10y-12=0
D=100-4*2*-12=196
y_1,y_2 = (10+-14)/4 
y_1 = 6
y_2 = -1 

x+2=4-6
x=4-6-2
x=-4

x+2=4+1
x=3

Answer: [y = 6; x = -4] U [y = -1 ; x = 3)