Решите . (2х-1)(3х+1)= (х-2)(3х-8)= (х+3)(х+5) (3а-1)(а+5) (2а+4)(3а-1)= (6а+2)(а-5) (2-6y)(y+11)=

(2х-1)(3х+1)=6x²-x-1
(х-2)(3х-8)=3x²-14x+16
(х+3)(х+5)=x²+8x+15
(3а-1)(а+5)=3a²+14a-5
(2а+4)(3а-1)=6a²+10a-4
(6а+2)(а-5)=6a²-28a-10
(2-6y)(y+11)=-6y²-64y+22