Решение:2cosx + √3 = 02cosx = - √3cosx = - √3/2x = ± arccos( - √3/2) + 2πn, n ∊ Zx = ± (π - arccos√3/2) + 2πn, n ∊ Zx = ± ( π - π/6) + 2πn, n ∊ Zх = ± 5π/6 + 2πn, n ∊ Zответ: = ± 5π/6 + 2πn, n ∊ Z.
Решение:
2cosx + √3 = 0
2cosx = - √3
cosx = - √3/2
x = ± arccos( - √3/2) + 2πn, n ∊ Z
x = ± (π - arccos√3/2) + 2πn, n ∊ Z
x = ± ( π - π/6) + 2πn, n ∊ Z
х = ± 5π/6 + 2πn, n ∊ Z
ответ: = ± 5π/6 + 2πn, n ∊ Z.