Решить систему y/3 + x/3=0,2 40x + 56y = 2,88

{ (x+5) / (y-3) = 0 > ОДЗ: (y-3) не = 0
{ 2y^2 + x^2 - y = 40
=>
{ x + 5 = 0 > x = -5
{ 2y^2 + (-5)^2 - y = 40 > 2y^2 - y - 15 = 0 > y1 = 3; y2 = -5\2