{2-i}{5}) (\frac{2+i}{10} )=\frac{(2-i)(2+i)}{50}=\frac{4-i^2}{50} =\frac{5}{50}= \frac{1}{10} =0,1[/tex]
{2-i}{5}) (\frac{2+i}{10} )=\frac{(2-i)(2+i)}{50}=\frac{4-i^2}{50} =\frac{5}{50}= \frac{1}{10} =0,1[/tex]