Решить (√5-4sin п/4 - 4cos^2 п/√1 - 3ctg^2 п/3)

(√5-4sinπ/4-4cos^2π/4)-(√(1-3ctg^2π/3)=
√(5-4*√2/2-4(√2/2)^2)-√(1-3(√3/3)^2)=
√(5-2√2-4*2/4)-√(1-3*3/9)=
√(3-2√2)=√(√2)^2-2√2+1)=√(√2-1)^2=
|√2-1|=√2-1