Решить 3(3-2i)+(5+3i) (2-i)^2 (1+2i)^3

3(3-2i)+(5+3i) = 9 - 6i + 5 + 3i = 14 - 3i
(2 - i)² = 4 - 4i + i² = 4 - 4i - 1 = 3 - 4i
(1 + 2i)³ = 1³ + 6i + 6i² + 8i³ = 1 + 6i - 6 + 8i * i² = -5 + 6i - 8i = -5 - 2i