5а³+45а^8 = 5а(а²+9а^7)
ах+3х+4а+12 = 3ах(4+12)
2х²-4ху²+3ху-6у³ = 2х(х-2у²)+3у(х-2у²) = (2х+3у)(х-2у²)
Если х = 1/4, а у = 1, то:
(2×1/4+3×1)(1/4-2×1²) = (2/4+3)(1/4-2) = 14/4×(-7/4) = 7/2×(-7/4) = -49/8 = -6 1/8
5а³+45а^8 = 5а(а²+9а^7)
ах+3х+4а+12 = 3ах(4+12)
2х²-4ху²+3ху-6у³ = 2х(х-2у²)+3у(х-2у²) = (2х+3у)(х-2у²)
Если х = 1/4, а у = 1, то:
(2×1/4+3×1)(1/4-2×1²) = (2/4+3)(1/4-2) = 14/4×(-7/4) = 7/2×(-7/4) = -49/8 = -6 1/8