По 1)2 cos^2 15градусов * tg15градусов 2)1-sin^2*22°30'

Решение
1)2 cos^2 15градусов * tg15градусов = (cos²15 * sin15)/ cos15 =
= (1/2)*sin30 = 1/4
2)1-sin^2*22°30' = cos²22°30' = (1 + cos45)/2 = 1/2 + (1/2)*√2/2 = 1/2 + √2/4