Найти производную функции : у=3х^4-2x^2+5x+7

(3х^4-2x^2+5x+7)'=3*4x^3+2*2x+5+0=12x^3+4x+5

F’(x) = (3*x^4 - 2*x² + 5*x +7)’ = (3*x^4 - 2*x² + 5*x)’ =
(3*x^4 - 2*x²)’ + (5*x)’ = (3*x^4)’ - (2*x²)’ + 5 = 3*(x^4)’ - 2*(x²)’ + 5 =
= 12x³ - 4*x + 5

f’(x) = 12x³ - 4x + 5