f(x) = (3-2x)¹⁶⁰
f'(x) = 160·(3-2x)¹⁵⁹·(3-2x)' = 160(3-2x)¹⁵⁹·(-2) = -320(3-2x)¹⁵⁹
ответ: -320(3-2x)¹⁵⁹.
f(x) = (3-2x)¹⁶⁰
f'(x) = 160·(3-2x)¹⁵⁹·(3-2x)' = 160(3-2x)¹⁵⁹·(-2) = -320(3-2x)¹⁵⁹
ответ: -320(3-2x)¹⁵⁹.