√(10+3x-x²) ≥ 0
(10+3x-x²) ≥ 0
x²-3x - 10 ≤ 0
(x-5)(x+2) ≤ 0
ответ: [-2; 5]
-x^2 + 3x + 10 >= 0 x^2 - 3x - 10 <= 0 (x - 5)(x + 2) <= 0 -2 <= x <= 5
√(10+3x-x²) ≥ 0
(10+3x-x²) ≥ 0
x²-3x - 10 ≤ 0
(x-5)(x+2) ≤ 0
ответ: [-2; 5]
-x^2 + 3x + 10 >= 0
x^2 - 3x - 10 <= 0
(x - 5)(x + 2) <= 0
-2 <= x <= 5