Найти cos t, tg t, ctg t, если sin t =5/13​

Cos^2 t = 1 - sin^2 t
cos^2t = 1 - 25/169 = 144/169
cos t = √144/169 = 12/13

tg t = sin t / cos t
tg t = 5/13 : 12/13 = 5/12

ctg t = 1 / tg t
ctg t = 12/5

ответ: cos t = 12/13, tg t = 5/12, ctg t = 12/5