(4a – 1) – (3a² – 4) – (6a – 1) + 2a² = 4a – 1 – 3a² + 4 – 6a + 1 + 2a² = –a² – 2a + 4, подставим a = –3: –(–3)² – 2(–3) + 4 = –9 + 6 + 4 = 1
ответ: 1
(4a – 1) – (3a² – 4) – (6a – 1) + 2a² = 4a – 1 – 3a² + 4 – 6a + 1 + 2a² = –a² – 2a + 4, подставим a = –3: –(–3)² – 2(–3) + 4 = –9 + 6 + 4 = 1
ответ: 1