Найдите производную функции f(x)=sin2x-cos3x

1)f(x)=sin2x-cos3x
cos(2x) d/dx [2x]+d/dx [-cos (3x)]
cos(2x)(2 d/dx [x])+d/dx [-cos (3x)]
cos(2x)*2+d/dx [-cos (3x)]
2*cos(2x)+d/dx [-cos (3x)]
2cos(2x)+d/dx [-cos (3x)]
2cos(2x)-d/dx [cos (3x)]
-(-sin(3x) d/dx [3x])
-(-sin(3x)(3 d/dx [x]))
2cos(2x)-(-sin(3x)(3*1))
2cos(2x)-(-sin(3x)*3)
2cos(2x)-(-3sin(3x))
2cos(2x)+3sin(3x)