x³-3x²+15+(12/(x-3))-5x+(12/(3-x))=0
x³-3x²-5x+15+(12/(x-3))-(12/(x-3))=0
x³-3x²-5x+15=0
x²(x-3)-5(x-3)=0
(x-3)*(x²-5)=0
(x-3)(x-√5)(x+√5)=0
x1= 3, x2= √5, x3= -√5
3+√5-√5= 3
x³-3x²+15+(12/(x-3))-5x+(12/(3-x))=0
x³-3x²-5x+15+(12/(x-3))-(12/(x-3))=0
x³-3x²-5x+15=0
x²(x-3)-5(x-3)=0
(x-3)*(x²-5)=0
(x-3)(x-√5)(x+√5)=0
x1= 3, x2= √5, x3= -√5
3+√5-√5= 3