Найдите корни квадратного трехчлена.
Dobriyboy
3
08.09.2019 14:07
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2
х^2+4х-5=0
D=b^2-4ac=16-4(1(-5))=16+20=36=6
x1=5
x2=1
Объяснение: a=1 b=4 c=-5
Д=в^2-4ас= 4^2-4*1*(-5)=16+20=36
Х1= - в+корень Д /2а=-4+6/2=1
Х2=-в-корень Д/2а=-4-6/2=-5
ответ: х1=1, х2=-5