По теореме Виета
x₁+x₂=4/3
x₁=-2
x₂=(4/3)-(-2)=(4/3)+2=(4/3)+(6/3)=10/3
x₁·x₂=-t/3
(-2)·(10/3)=-t/3
t=20
По теореме Виета
x₁+x₂=4/3
x₁=-2
x₂=(4/3)-(-2)=(4/3)+2=(4/3)+(6/3)=10/3
По теореме Виета
x₁·x₂=-t/3
(-2)·(10/3)=-t/3
t=20