5x^2-36x+7=0 3x^2+x-4=0 -найти дискриминант

5x²=-36x+7=0
D=1296-140=1156 = 34²
x1=36+34/10 =70/10 =7
x2=36-34/10 =2/10 = 1/5
x1=7 , x2=1/5

3x²+x-4=0
D=1+48 = 49 =7²
x1=-1+7/6 = 6/6 = 1 
x2=-1-7/6 =  -8/6 = - 4/3

x1=1 , x2= - 4/3