4x-y=3. 2x^2+y^2=3 розв'яжiть систему рiвнянь

Y = 4x - 3
2x^2 + 16x^2 - 24x + 9 = 3
18x^2 - 24x + 6 = 0
6( 3x^2 - 4х + 1 ) = 0
D = 16 - 12 = 4 = 2^2
X1 = ( 4 + 2 ) : 6 = 1
X2 = ( 4 - 2 ) : 6 = 1/3
y = 4x - 3
y1 = 4•1 - 3 = 1
y2 = 4•( 1/3 ) - 3 = 1 1/3 - 2 3/3 = - 1 2/3
ответ ( 1 ; 1 ) ; ( 1/3 ; - 1 2/3 )