4cos2x+3sin2x-5=0
a){arctg3}
b){arctg1/3+pn,n€z}
c){p/4+pn, n€z}
d){arctg3+pn,n€z}

Question

Алгебра: 4cos2x+3sin2x-5=0 a){arctg3} b){arctg1/3+pn,n€z} c){p/4+pn, n€z} d){arctg3+pn,n€z}

лейоа · Answer

Объяснение:4cos2x+3sin2x=5 -5 + 4cos(2x) + 3sin(2x) = 0 - (cosx - 3sinx)^2 = 0 (cosx - 3sinx)^2 = 0 (cosx - 3sinx) = 0 cosx = 3sinx    /cosx ≠ 0 tgx = 1/3 x = arctg(1/3) + πn, n∈Z...

4cos2x+3sin2x-5=0 a){arctg3} b){arctg1/3+pn,n€z} c){p/4+pn, n€z} d){arctg3+pn,n€z}

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4cos2x+3sin2x-5=0
a){arctg3}
b){arctg1/3+pn,n€z}
c){p/4+pn, n€z}
d){arctg3+pn,n€z}