3. 12у – 20у= 4у( 3-5)
4. (х+2а)² = х² + 4ax+ 4а²
(7+2х)² = 49 + 28х 4х²
(3-5х)² = 9- 30xy +25х²
(4a-3)² =16а²- 24а+ 9
3. 12у – 20у= 4у( 3-5)
4. (х+2а)² = х² + 4ax+ 4а²
(7+2х)² = 49 + 28х 4х²
(3-5х)² = 9- 30xy +25х²
(4a-3)² =16а²- 24а+ 9