(2a-3)(a+4)-(4a+2)(8a-6)=
=2a^2+8a-3a-12-(32a^2-24a+16a-12) =
=2a^2+8a-3a-12-(32a^2-8a-12)=
=2a^2+8a-3a-12-32a^2+8a+12=
=2a^2+8a-3a-32a^2+8a=-30a^2+13a
ответ: -30a^2+13a
(2a-3)(a+4)-(4a+2)(8a-6)=
=2a^2+8a-3a-12-(32a^2-24a+16a-12) =
=2a^2+8a-3a-12-(32a^2-8a-12)=
=2a^2+8a-3a-12-32a^2+8a+12=
=2a^2+8a-3a-32a^2+8a=-30a^2+13a
ответ: -30a^2+13a