1) (x+7)/(x-2)-1=(36)/(x^(2)-4) 2) (x-5)/(x+3)+(8)/(x-3)=(43)/(x^(2)-9)
3) (x-6)/(x+1)-(2+x)/(x-1)=(8)/(x^(2))
4) (x+3)/(x-8)-(x-12)/(x+1)=(99)/((x-8)(x+1))

Question

Алгебра: 1) (x+7)/(x-2)-1=(36)/(x^(2)-4) 2) (x-5)/(x+3)+(8)/(x-3)=(43)/(x^(2)-9) 3) (x-6)/(x+1)-(2+x)/(x-1)=(8)/(x^(2)) 4) (x+3)/(x-8)-(x-12)/(x+1)=(99)/((x-8)(x+1))

хорошист546 · Answer

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1) (x+7)/(x-2)-1=(36)/(x^(2)-4) 2) (x-5)/(x+3)+(8)/(x-3)=(43)/(x^(2)-9) 3) (x-6)/(x+1)-(2+x)/(x-1)=(8)/(x^(2)) 4) (x+3)/(x-8)-(x-12)/(x+1)=(99)/((x-8)(x+1))

Популярные вопросы

1) (x+7)/(x-2)-1=(36)/(x^(2)-4) 2) (x-5)/(x+3)+(8)/(x-3)=(43)/(x^(2)-9)
3) (x-6)/(x+1)-(2+x)/(x-1)=(8)/(x^(2))
4) (x+3)/(x-8)-(x-12)/(x+1)=(99)/((x-8)(x+1))