1.(x+5)^2+(x-2)^2+(x-7)(x+7)=11x+ 2.(x-4)(4x-3)+3=0 3.(3x-1)(x+2)=20 ))

Question

Алгебра: 1.(x+5)^2+(x-2)^2+(x-7)(x+7)=11x+ 2.(x-4)(4x-3)+3=0 3.(3x-1)(x+2)=20 ))

elaushkop0busc · Answer

2) 4x^2-3x-16x+12+3=04x^2-19x+15=0D=361-240=121=11^2x=(19⁺₋11)/8x1=(19+11)/8=30/8=3.75x2=(19-11)/8=8/8=13)3x^2+6x-x-2=203x2+6x-x-2-20=03x2+5x-22=0D=25+4*3*22=25+264=289=17^2x1=(-5-17)/6=-22   x2= (-5+17)/6=12/6=2...

1.(x+5)^2+(x-2)^2+(x-7)(x+7)=11x+ 2.(x-4)(4x-3)+3=0 3.(3x-1)(x+2)=20 ))

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