1) (x + 2) - (x - 2) = 2x (6x + 2);(2) (x + 3)³ - (x – 4)³ = 21x² + 7;

Question

Алгебра: 1) (x + 2) - (x - 2) = 2x (6x + 2);(2) (x + 3)³ - (x – 4)³ = 21x² + 7;​

dniill · Answer

ответ:ОДЗ:

x ≠ 0

x ≠ -2

[ (2x-3) / x ] - 1 / (x+2) = (4x-6) / (x^2+2x)

(2x^2-3x+4x-6-x) / (x^2+2x) = (4x-6) / (x^2+2x)

2x^2 - 6 = 4x-6

2x^2 - 4x = 0

2x * (x - 2) = 0

x1 = 0; x2 = 2

Объяснение:

1) (x + 2) - (x - 2) = 2x (6x + 2);
(2) (x + 3)³ - (x – 4)³ = 21x² + 7;