1) tg (5 arctg √ 3/3 - 1/4 arcsin √ 3/2 ) 2) sin ( arcctg (- √3) + arctg (- √3) + arcsin 1/2)

Question

Алгебра: 1) tg (5 arctg √ 3/3 - 1/4 arcsin √ 3/2 ) 2) sin ( arcctg (- √3) + arctg (- √3) + arcsin 1/2)

witin2394j · Answer

1) tg (5 arctg √ 3/3 - 1/4 arcsin √ 3/2 )=tg (5* pi/6 - 1/4* pi/3 )=tg(5pi/6-pi/12)=tg(9pi/12)=tg(3pi/4)=-1

2) sin ( arcctg (- √3) + arctg (- √3) + arcsin 1/2)=sin(5pi/6-pi/3+pi/6)=sin(4pi/6)=sin(2pi/3)=√3/2