1)sin(x-pi/4)=1 2)sin(x/4)*cos(x/4)=-1/4 3)(cos2x+cospi/4)*(cos2x+4)=0 {0; pi} 4)sqrt3cosx+sin2x=0 5)sinx+sin5x=0 6)sin^2x-0.5sin2x=0 7)sin2x+sin6x=cos2x

Question

Алгебра: 1)sin(x-pi/4)=1 2)sin(x/4)*cos(x/4)=-1/4 3)(cos2x+cospi/4)*(cos2x+4)=0 {0; pi} 4)sqrt3cosx+sin2x=0 5)sinx+sin5x=0 6)sin^2x-0.5sin2x=0 7)sin2x+sin6x=cos2x 8)3sin^2x+3cosx*sinx+2cos^2x=1

narmanbet · Answer

Решение в приложении......

1)sin(x-pi/4)=1 2)sin(x/4)cos(x/4)=-1/4 3)(cos2x+cospi/4)(cos2x+4)=0 {0; pi} 4)sqrt3cosx+sin2x=0 5)sinx+sin5x=0 6)sin^2x-0.5sin2x=0 7)sin2x+sin6x=cos2x 8)3sin^2x+3cosx*sinx+2cos^2x=1

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