1) 1/cos^2(a) – tg^2(a)-sin^2(a) 2) cos^2(a)+ctg^2(a)-1/sin^2(a) 3) 1/cos^2(a) – tg^2(a)(cos^2(a)+1) 4) (1+sin^2(a))ctg^2(a) – 1/sin^2(a) 5)sin(a)/(1+cos(a)) + sin(a)/(1-cos(a)) 6)cos(a)/(1+sin(a))+ cos(a)/(1-sin(a))

ilia200575 ilia200575    2   23.04.2019 21:30    1

Ответы
DianaSagatbekova DianaSagatbekova  08.06.2020 11:48
1)
1/cos^2(a) – tg^2(a)-sin^2(a)= 1/cos^2(a) – sin^2(a)/cos^2(a))-sin^2(a)=
=[1 – sin^2(a) ]/cos^2(a))-sin^2(a)=cos^2(a)/cos^2(a))-sin^2(a)=
=1-sin^2(a)=cos^2(a)
2)
cos^2(a)+ctg^2(a)-1/sin^2(a)=cos^2(a)+[cos^2(a)-1]/sin^2(a)=
=cos^2(a)-sin^2(a)]/sin^2(a)=cos^2(a)-1 = -sin^2(a)
3)
1/cos^2(a) – tg^2(a)(cos^2(a)+1)=1/cos^2(a) – sin^2(a)-sin^2(a)/(cos^2(a)=
=(1 – sin^2(a))/cos^2(a)-sin^2(a)=1-sin^2(a)=cos^2(a)

4) (1+sin^2(a))ctg^2(a) – 1/sin^2(a)=cos^2/sin^2 +cos^2 – 1/sin^2(a)=
=(cos^2 - 1)/sin^2 +cos^2= -sin^2/sin^2 +cos^2= -1+cos^2=  -sin^2(a)
 
5)sin(a)/(1+cos(a)) + sin(a)/(1-cos(a))=sin(a) *  ((1-cosa)+(1+cosa)) / (1-cos^2)=2/sin(a)
 
6)cos(a)/(1+sin(a))+ cos(a)/(1-sin(a))=cos(a)* ((1-sina+1+sina)) / (1-sin^2a)= 2/cos(a)
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