Выполните сложение: 1)3 1/15+2 7/25; 2)2 7/10+9 2/15; 3)9 5/18+6 1/12; 4)1 7/12+3 5/9; 5)5 5/24+2 1/6; 6)3 1/12+4 2/15; аригато

Ответы

dreytes 20.09.2020 12:25

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$\boldsymbol{1)} \:\:\: 3\dfrac{{1}^{(\cdot5}}{{15}^{(\cdot5}}+2\dfrac{{7}^{(\cdot3}}{{25}^{(\cdot3}}=3\dfrac{5}{75}+2\dfrac{21}{75}=\Big(3+2\Big)+\Big(\dfrac{5+21}{75}\Big)=\boldsymbol{5\dfrac{26}{75}}$

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$\boldsymbol{2)} \:\:\: 2\dfrac{{7}^{(\cdot3}}{{10}^{(\cdot3}}+9\dfrac{{2}^{(\cdot2}}{{15}^{(\cdot2}}=2\dfrac{21}{30}+9\dfrac{4}{30}=\Big(2+9\Big)+\Big(\dfrac{21+4}{30}\Big)=11\dfrac{{25}^{(:5}}{{30}^{(:5}}=\boldsymbol{11\dfrac{5}{6}}$ ============================================================ $\boldsymbol{3)} \:\:\: 9\dfrac{{5}^{(\cdot2}}{{18}^{(\cdot2}}+6\dfrac{{1}^{(\cdot3}}{{12}^{(\cdot3}}=9\dfrac{10}{36}+6\dfrac{3}{36}=\Big(9+6\Big)+\Big(\dfrac{10+3}{36}\Big)=\boldsymbol{15\dfrac{13}{36}}$

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$\boldsymbol{4)} \:\:\: 1\dfrac{{7}^{(\cdot3}}{{12}^{(\cdot3}}+3\dfrac{{5}^{(\cdot4}}{{9}^{(\cdot4}}=1\dfrac{21}{36}+3\dfrac{20}{36}=\Big(1+3\Big)+\Big(\dfrac{21+20}{36}\Big)=4+1\dfrac{5}{36}=\boldsymbol{5\dfrac{5}{36}}$ ============================================================

$\boldsymbol{5)} \:\:\: 5\dfrac{5}{24}+2\dfrac{{1}^{(\cdot4}}{{6}^{(\cdot4}}=5\dfrac{5}{24}+2\dfrac{4}{24}=\Big(5+2\Big)+\Big(\dfrac{5+4}{24}\Big)=7\dfrac{{9}^{(:3}}{{24}^{(:3}}=\boldsymbol{7\dfrac{3}{8}}$

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$\boldsymbol{6)} \:\:\: 3\dfrac{{1}^{(\cdot5}}{{12}^{(\cdot5}}+4\dfrac{{2}^{(\cdot4}}{{15}^{(\cdot4}}=3\dfrac{5}{60}+4\dfrac{8}{60}=\Big(3+4\Big)+\Big(\dfrac{5+8}{40}\Big)=\boldsymbol{7\dfrac{13}{40}}$