Решите 1) x^2+13x+12=0 2) x^2+2x-8=0, запишите квадратное уравнение 1) x1=5 x2=-3, 2) x1=-10 x2=-6

1) x² + 13x + 12 = 0 x₁ + x₂ = - 13 x₁x₂ = 12 x₁ = - 1; x₂ = - 12 2) x₁ = 5; x₂ = -3 x₁ + x₂ = 2; x₁x₂ = - 15 x² - 2 - 15 = 0 3) x₁ = - 10; x₂ = - 6 x₁ + x₂ = - 16; x₁x₂ = 60 x² + 16 + 60 = 0