дано
m(ZnO) = 24.3 g
m(Zn(OH)2)-?
Zn(OH)2-->ZnO+H2O
M(ZnO) = 81 g/mol
n(ZnO) = m/M = 24.3 / 81 = 0.3 mol
n(Zn(OH)2) = n(ZnO) = 0.3 mol
M(Zn(OH)2) = 99 g/mol
m(Zn(OH)2) = n*M = 0.3 * 99 = 29.7 g
ответ 29.7 г
дано
m(ZnO) = 24.3 g
m(Zn(OH)2)-?
Zn(OH)2-->ZnO+H2O
M(ZnO) = 81 g/mol
n(ZnO) = m/M = 24.3 / 81 = 0.3 mol
n(Zn(OH)2) = n(ZnO) = 0.3 mol
M(Zn(OH)2) = 99 g/mol
m(Zn(OH)2) = n*M = 0.3 * 99 = 29.7 g
ответ 29.7 г