45 ! с2h60 al04 найдите малекулярную массу

M(C₂H₆O)=M(C)*2+M(H)*6+M(O)*1=12*2+6*1+16*1=46
M(AlPO₄)=M(Al)*1+M(P)*1+M(O)*4=27*1+31*1+16*4=122

C2H6O
C2H6O=12*2+1*6+16=46
W(C)=24*100/46=52,2%
W(H)=6*100/46=13%
W(O)=16*100/46=34,8%

AlPO4
AlPO4=27+16*4=122
W(Al)=27*100/122=22,1%
W(P)=31*100/122=25,4%
W(O)=64*100/122=52,5%