(3x-1)²+(x-2)(x+2) = 1
(3x)²-2·3x·1+1²+(x²-2²) = 1
9x²+x²-6x+1-4-1 = 0
10x²-6x-4 = 0
10x²+4x-10x-4 = 0
x(10x+4)-(10x+4) = 0
(10x+4)(x-1) = 0
10x+4=0 или x-1=0
x= -4:10= -0,4 или x=1
ответ: -0,4; 1.
(3x-1)²+(x-2)(x+2) = 1
(3x)²-2·3x·1+1²+(x²-2²) = 1
9x²+x²-6x+1-4-1 = 0
10x²-6x-4 = 0
10x²+4x-10x-4 = 0
x(10x+4)-(10x+4) = 0
(10x+4)(x-1) = 0
10x+4=0 или x-1=0
x= -4:10= -0,4 или x=1
ответ: -0,4; 1.