Решите уравнение 2sin23x -3sin3x +1=0
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12.05.2019 10:01
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Объяснение:
2*sin²(3x)-3*sin(3x)+1=0
Пусть sin(3x)=t ⇒
2t²-3t+1=0 D=1
t₁=sin(3x)=1 3x=π/2+2πn |÷3 x₁=π/6+2π/3.
t₂=sin(3x)=1/2 ⇒
3x=π/6+2πn |÷3 x₂=π/18+2π/3.
3x=5π/6+2πn |÷3 x₃=5π/18+2π/3.
Решение во вложении