а)1/8 - а³=(0,5)³-a³=(0.5-a)(0.5²+0.5a+a²)=(0.5-a)(0.25+0.5a+a²)
б)125+b³=5³+b³=(5+b)(5²-5b+b²)=(5+b)(25-5b+b²)
в)а³+b³=(a+b)(a²-ab+b²)
г)1-64а³=1³-(4a)³=(1-4a)(1²+4a+(4a)²)=(1-4a)(1+4a+16a²)
а)1/8 - а³=(0,5)³-a³=(0.5-a)(0.5²+0.5a+a²)=(0.5-a)(0.25+0.5a+a²)
б)125+b³=5³+b³=(5+b)(5²-5b+b²)=(5+b)(25-5b+b²)
в)а³+b³=(a+b)(a²-ab+b²)
г)1-64а³=1³-(4a)³=(1-4a)(1²+4a+(4a)²)=(1-4a)(1+4a+16a²)