=2(c+d)-(c^2+2cd+d^2)=2(c+d)-(c+d)^2=
=(c+d)(2-c-d)=(2/3+1/6)(2-2/3-1/6)=
=(4/6+1/6)(2-4/6-1/6)=5/6(2-5/6)=
=5/6×1 1/6=5/6×7/6=35/36
Пошаговое объяснение:
=2(c+d)-(c^2+2cd+d^2)=2(c+d)-(c+d)^2=
=(c+d)(2-c-d)=(2/3+1/6)(2-2/3-1/6)=
=(4/6+1/6)(2-4/6-1/6)=5/6(2-5/6)=
=5/6×1 1/6=5/6×7/6=35/36
Пошаговое объяснение: